x^2-280x+16000=0

Solution for x^2-280x+16000=0 equation:

x^2-280x+16000=0

a = 1; b = -280; c = +16000;
Δ = b2-4ac
Δ = -2802-4·1·16000
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-280)-120}{2*1}=\frac{160}{2}
=80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-280)+120}{2*1}=\frac{400}{2}
=200
$